A major leaguer hits a baseball so that it leaves the bat at a speed of 28.0 m/s

Question

A major leaguer hits a baseball so that it leaves the bat at a speed of 28.0 m/s and at an angle of35.3 degrees above the horizontal. You can ignore air resistance.

Part A) Answer: 0.708 s, 2.59 s

B) Calculate the horizontal component of the baseball's velocity at each of the two times you found in part A.

= _______ m/s

D) What is the magnitude of the baseball's velocity when it returns to the level at which it left the bat?

v = 28.0 m/s

E) What is the direction of the baseball's velocity when it returns to the level at which it left the bat?

= _______ degrees below the horizontal

Explanation / Answer

B)thehorizontal component of velocity will be the same in both the cases and will be equal to 28cos35.3

=22.85 m/s

D)35.3 degrees below the horizontal

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