017 (part 1 of 3) 10.0 points A generator at Hoover Dam can supply 388 MW of ele

Question

017 (part 1 of 3) 10.0 points A generator at Hoover Dam can supply 388 MW of electrical power. Assume that the turbine and the generator are 89.7% e?- cient. Find the rate with which falling water must supply energy to the turbine. The acceleration due to gravity is 9.8 m/s 2 . Answer in units of MW 018 (part 2 of 3) 10.0 points The energy of the water comes from the change of the potential energy (m g h). What is the needed change in potential energy each second? Answer in units of J/s 019 (part 3 of 3) 10.0 points If the water falls 22.8 m, what is the mass of the water that must pass through the turbine each second to supply this power? Answer in units of kg/s

Explanation / Answer

1) RawPower *0.803 = 385

RawPower = 479.45 MW

2) PE per second = Raw Power

(479.45 MW = 479.45 *10^6 J/s^3) mgh = ) PE (this is an equation for 'per second'

(m = PE / g h = 479.45 * 10^6/9.8 *22.8 = 2.14 * 10^6 kg/s)

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