010W History Bookmarks People Window Hel 58% Tue 10:24 PM a :E Assessment And E

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010W History Bookmarks People Window Hel 58% Tue 10:24 PM a :E Assessment And E × usu Home-myLSU xWileyPLUS https://edugen.wileyplus.com/edugen/student/mainfr.uni ctice Assignment Gradebook ORIONDownloadable eTextbook ment FULL SCREEN PRINTER VERSION ·BACK NEXT Chapter 06, Problem 35 Your answer is partially correct. Try again. A 61.6-kg skateboarder starts out with a speed of 1.63 m/s. He does 80.3 J of work on himself by pushing with his feet against the doing the work are non-conservative. The final speed of the skateboarder is 6.84 m/s. (a) Calculate the change (PE - PEo) in the of work on him. In both cases, the forces non-conservative. The final gravitational potential energy. (b) How much has the vertical height of the skater changed? Give the absolute value. (a) Number T-1537.9 (b) N 2.2 SHOW HINT LINK TO TEXT LINK TO TEXT Question Attempts: Unlimited SAVE FOR LATER SUBMET ANSWER 3

Explanation / Answer

a) Work done W = delta KE + delta PE

delta KE = 1/2 m vf2 - 1/2 m vo2 = 0.5 * 61.6 [6.842 - 1.632] = 1359 J

delta PE = 80.3 -259 - 1359 = -1537.7 J

b) delta PE = m g (h - h0)

h - h0 = delta PE / m g = -1537.7 / (61.6 * 9.8)

h - h0 = -2.55 m

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