Suppose a 100 kg car traveling at 3 m/s hits a 50 kg car traveling at 2 m/s. Aft

Question

Suppose a 100 kg car traveling at 3 m/s hits a 50 kg car traveling at 2 m/s. After they collide, they stick together and move at 1 m/s. How much kinetic energy was lost in this collision?

Explanation / Answer

FOLLOW THIS Use Conservation of Momentum to find the resulting velocity. Then calculate the difference in Initial Kinetic Energy and Final... x-axis -> west east (west is negative) y-axis -> north south (south is negative) Calculate the p1 and p2 for EACH car (just by multiplying mv)... then you have the following equations: px: p2 = (m1 + m2)vx py: p1 = (m1 + m2)vy Calculate (vx, vy) the velocity of the two-car-system. Use this to calculate Kinetic energy: T =

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.