Two small speakers are driven by a common oscillator at 7.35 102 Hz. The speaker

Question

Two small speakers are driven by a common oscillator at 7.35 102 Hz. The speakers face each other and are separated by 1.28 m. Locate the points along a line joining the two speakers where relative minima would be expected. (Use v = 343 m/s. Choose one speaker as a reference and enter your answers as positive distances from this speaker, from smallest to largest. Enter NONE in unused answer boxes.) There should be six values I tried 2x-1.28=(n+1/2)lamda and x=1.28-lamda/2 neither seem to give correct answers i have lamda as .47

Explanation / Answer

lamda = c/f = 343/735 = 0.46667 m

x - (L - x) = 2x - L

2x - 1.28 = 0.46667/2

2x = 1.513335

==> x0 = 0.7566675

==> x1 = 0.7566675 + lamda = 0.7566675 + 0.46667 = 1.2233375

==> x2 = 0.7566675 - lamda = 0.7566675 - 0.46667 =0.2899975

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