A rope is pulling horizontally to the right on a box of weight 34.0 N which is s

Question

A rope is pulling horizontally to the right on a box of weight 34.0 N which is sliding across the floor at a constant speed. The coefficient of kinetic friction between the floor and the box is 0.710. A.What is the magnitude and direction of the normal force from the floor acting on the box? (Direction up, down, left, or right? B.What is the magnitude and direction of the frictional force acting on the box? (Direction: up, down, left, or right?) C.What is the magnitude of the tension in the rope which is pulling the box?

Explanation / Answer

Part A)

The normal force always acts perpendiculat to the two surfaces. Thus the floor must push up on the box. So the answer is up.

Part B)

Friction always acts against the direction of motion, so since the rope pulls to the right, friction must pull to the left. So the answer is to the left.

Part C)

The applied force , the Tension, balances friction and found by the formula

(F_{f}= mu F_{n})

Since Ff is equal to the Tension, then

T = (.710)(34)

T = 24..1 N

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