2. Some extreme sport enthusiasts have been know to jump off the top of El Capit

Question

2. Some extreme sport enthusiasts have been know to jump off the top of El Capitan, a sheer granite cliff of height 910.0 m in Yosemite National park. Assume a jumper runs horizontally off the top of El Capitan with a speed of 4.2 m/s. The person enjoys free-fall until 144.5 m from the ground, at which time he/she opens a parachute. (i) How long (time) is the person in free-fall? (ii) It is very important that the parachute be far away from the cliff when opened. How far is the jumper from the cliff when opening the parachute?

Explanation / Answer

follow this for part a, we note that there was no initial vertical velocity, so we can calculate how long she was in free fall from distance = 1/2 gt^2 where g is the accel due to gravity and t is the time here, the distance of freefall = 910 m - 150 m = 760m and find the time from t=sqrt[2*760m/9.8m/s/s] since there are no horizontal forces, the horizontal speed is constant throughout the trip (until the parachute is deployed) therefore, the diver travels a horizontal distance of 5m/s x time of freefall (which you just computed above)

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