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Two carts on a track have the same mass m = 1.00 kg. They collide elastically wi

ID: 2231844 • Letter: T

Question

Two carts on a track have the same mass m = 1.00 kg. They collide elastically with Cart 1 initially traveling at v1i, = 1.30 m/s to the right and Cart 2 initially at rest (V2i = 0 m/s). The collision is monitored by two motion sensors. The time over which the collision lasts is deltat = 0.11 s. What is the final velocity of Cart 1? v1f = What is the final velocity of Cart 2? V2f = what is the change in kinetic energy of each Cart? What is the impulse delivered to cart 2 ? What is the average force of Cart 1 on cart 2 during the collision ? Average F12 = What is the average force of Cart 2 on cart 1 during the collision? Average F21= Two carts on a track have the same mass m = 0.90 kg. They collide completely inelastically with Cart 1 initially traveling at v1i = 0.78 m/s to the right and Cart 2 initially at rest (V2i = 0 m/s). The collision is monitored by two motion sensors. The time over which the collision lasts is deltat = 0.09 s. What is the final velocity of Cart 1? What is the final velocity of Cart 2? What is the change in kinetic energy of each Cart? What is the impulse delivered to cart 2? What is the average force of Cart 1 on Cart 2 during the collision? Average F12 = what is the average force of Cart 2 on Cart 1 during the collision ? Average F21 = Two carts on a track have the same mass m = 0.90 kg. They collide completely inelastically with Cart 1 initially traveling at vu = 0.78 m/s to the right and Cart 2 initially at rest (V2/ = 0 m/s). The collision is monitored by two motion sensors. The time over which the collision lasts is deltat = 0.09 s. What is the final velocity of Cart 1? What is the final velocity of Cart 2? What is the change in kinetic energy of each Cart? What is the impulse delivered to cart 2? What is the average force of Cart 1 on Cart 2 during the collision? Average F12 = What is the average force of Cart 2 on Cart 1 during the collision? Average F21 = Two carts on a track have the same mass m = 1.00 kg. They collide elastically with Cart 1 initially traveling at v1i, = 1.30 m/s to the right and Cart 2 initially at rest (V2i = 0 m/s). The collision is monitored by two motion sensors. The time over which the collision lasts is deltat = 0.11 s.What is the final velocity of Cart 1? What is the final velocity of Cart 2? v21 = What is the change in kinetic energy of each Cart? What is the impulse delivered to cart 2? What is the average force of Cart 1 on Cart 2 during the collision? Average F12 = What is the average force of Cart 2 on Cart 1 during the collision? Average F21 = Two carts on a track have the same mass m = 1.00 kg. They collide elastically with Cart 1 initially traveling at v1i, = 1.30 m/s to the right and Cart 2 initially at rest (V2i = 0 m/s). The collision is monitored by two motion sensors. The time over which the collision lasts is deltat = 0.11 s. What is the final velocity of Cart 1? What is the final velocity of Cart 2? v21= What is the change in kinetic energy of each Cart? What is the impulse delivered to cart 2? What is the average force of Cart 1 on Cart 2 during the collision? Average F12 = What is the average force of Cart 2 on Cart 1 during the collision? Average F21 = Two carts on a track have the same mass m = 1.00 kg. They collide elastically with Cart 1 initially traveling at v1i, = 1.30 m/s to the right and Cart 2 initially at rest (V2i = 0 m/s). The collision is monitored by two motion sensors. The time over which the collision lasts is At = 0.11 s. What is the final velocity of Cart 1? 2. What is the final velocity of Cart 2? v21 = What is the change in kinetic energy of each Cart? What is the impulse delivered to cart 2? What is the average force of Cart 1 on Cart 2 during the collision? Average F12 = 6. What is the average force of Cart 2 on Cart 1 during the collision? Average F21 =

Explanation / Answer

it's a repetition of the same formulas

m1v1 + m2v2 = m1v1' + m2v2'

change in kinetic = final - initial = 0.5mvf^2 - 0.5mvi^2

impulse = change in momentum = mvf - mvi

forces are always gonna be the same due to newton's 3rd law and it's impulse/time

just comment if you need more help

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