Two electric dipoles with charges +Q, where Q = 11.5 mC, are arranged as shown i
ID: 2228667 • Letter: T
Question
Two electric dipoles with charges +Q, where Q = 11.5 mC, are arranged as shown in the Figure. The charges +Q on the left are attached to each other by a rigid rod, and the two charges on the right are also rigidly attached to each other. Find the magnitude of the electric force between the two dipoles. https://media.cheggcdn.com/media/01d/01df42ce-9241-4695-a8cd-d32fd98f7299/phpZvNDqv.png The values ive tried are: 21160N,529000N,84640N,2116000N,1190250N,0N,1.5N,172.5N,34.5N,20250N, 86.25*10^-3N,8.4099*10^-4N,8.4099E-4N,-8.4099E-4N,8.434E-4N,750.03 N,25.45 N And none of them are right PLZ HELPExplanation / Answer
D =sqrt(1.5^2+7.5^2) =7.649 m
F1 = 2*9*10^9*11.5*11.5*10^-6/7.5^2
=42320 N
F2 = 9*10^9*11.5*11.5*10^-6/7.649^2
=20391.608 N
F(net) = 42320 - 2*20391.608*7.5/7.649
= 2331.227 N
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