Two electric dipoles with charges +Q, where Q = 5 mC, are arranged. The charges

Question

Two electric dipoles with charges +Q, where Q = 5 mC, are arranged. The charges +Q on the left are attached to each other by a rigid rod, and the two charges on the right are also rigidly attached to each other. Find the magnitude of the electric force between the two dipoles. The following is the answer when Q=1.5 mC, but I need an answer for 5 mC CLEARLY THE force will be along x - axis all y direction component will cancel. force between Q and Q (SAME SIGN)= kq^2/r^2 = k * (1.5e-3)^2/7.5^2 = 360N force between +ive and -ive along x-axis is = [kq^2 /(7.5^2 + 1.5^2) ]* [7.5/?(7.5^2 + 1.5^2)] = 339.43N there force net force on one charge = 360-339.432 = 20.568 N is force on one charge i.e. force on two charges = 2*20.568= 41.136N is net force on each dipole

Explanation / Answer

Force F=k xQ1 xQ2/ r^2 =>F = 9x10^9x5x10^-3x5x10^-3/r^2 =>F = 225/r^2 Coloumb

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