A rock thrown with speed 10.5 and launch angle 30.0(above the horizontal) travel

Question

A rock thrown with speed 10.5 and launch angle 30.0(above the horizontal) travels a horizontal distance of = 18.0before hitting the ground. From what height was the rock thrown? Use the value = 9.810 for the free-fall acceleration. A rock thrown with speed 10.5 and launch angle 30.0(above the horizontal) travels a horizontal distance of = 18.0before hitting the ground. From what height was the rock thrown? Use the value = 9.810 for the free-fall acceleration. a.)Find the height (yi) from which the rock was launched. Express your answer in meters to three significant figures. b.)A second rock is thrown straight upward with a speed 5.250 m/s. If this rock takes 1.979 seconds to fall to the ground, from what height was it re leased? Express your answer in meters to three significant figures.

Explanation / Answer

Initial vertical vel, Vv = 10.5.sin30 = 5.25m/s Initial horiz. vel, Vh = 10.5.cos30 = 9.09m/s Time of flight, t = 18.0m / Vh t = 18.0 / 9.09 t = 1.98s Vertical displacement (s) after 1.98s = distance to ground ( launch height) s = (Vv.t) -

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.