I\'m having a little trouble figuring out part B of this. I already determined t

Question

I'm having a little trouble figuring out part B of this. I already determined the answer of A to be 29700V. Can somebody please explain how to solve part B? Thanks!

On a clear day the electric field in the atmosphere near the earth's surface is 100 N/C, directed vertically downward.

(a) If we adopt the convention that the potential at the earth's surface is 0, what is the potential 297 m above the surface?


(b) What is the potential at the top of Pike's Peak, 14,110 ft above sea level? (Hint: Do not assume that the surface in part (a) is at sea level.)

Explanation / Answer

(b) As we know 1 feet = 0.305 m,
14110 ft = 4300.73 m.
Accordingly, the potential at that height is 0 + E*h
=> V = 100 *4300.73 = 430073 V

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