A cheetah is traveling across the African countryside, initially moving at a con

Question

A cheetah is traveling across the African countryside, initially moving at a constant velocity of 15 m/s. It sees a gazelle at t = 0 seconds and begins to accelerate in a straight line. At t = 4.0 seconds it has a velocity of 23 m/s and then continues to move at this constant velocity. At t = 5.0 seconds, the cheetah is standing still, having knocked over the gazelle. (a) What is the average acceleration of the cheetah from t = 0 to t = 4.0 seconds? (b) What is the average acceleration of the cheetah from t = 0 to t = 5.0 seconds?

Explanation / Answer

v = v0 + at = 13 + 4*a = 23

a = 2.5 m/s^2

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