You have a tank of water sitting on a table and water is squirting out a spigot

Question

You have a tank of water sitting on a table and water is squirting out a spigot on the side. The water is leaving the tank traveling horizontally at a speed of 3.54 m/s. The spigot is a height h=1.49 m above the ground. How fast is the water traveling vertically just as it leaves the spigot? How fast is the water traveling horizontally just as it leaves the spigot? While the water is in the air, what are the x and y components of the acceleration? How much time elapses between when the water leaves the spigot and when it hits the ground? (Hint: You don

Explanation / Answer

initial horizontal velocity = 3.54 m/s
initial vertical velocity = 0 m/s
horizontal acceleration = 0 m/s^2
vertical acceleration = g = 9.8 m/s^2
vertical height = 1.49 m
so time taken untill it reaches ground => h=ut+0.5at^2
u=0, h=1.49
1.49=0.5*9.8*t^2
t=0.5514s

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