/Users/library/Desktop/Screen shot 2013-01-28 at 2.29.50 PM.png Two charges are
ID: 2225321 • Letter: #
Question
/Users/library/Desktop/Screen shot 2013-01-28 at 2.29.50 PM.png Two charges are fixed in place on the x-axis as shown. The charge at x = 0 is negative and has magnitude q = 2.0 ?Coulombs (1 ?Coulomb = 10-6 Coulombs). The charge at x = d, (d = +12.0 cm), is positive and has magnitude Q = 4.0 ?Coulombs. Find a point x = xo along the x-axis at which the electric field is zero. xo =Explanation / Answer
Let Electric field be 0 at a distance x to the left of -ve charge Electrical field cannot be zero in between them as charges are opposite E1 =E2 as net electric field =0 =>k*q1/(x^2) = k*q2/((d+x)^2) =>k*2*micro coulomb/(x^2) = k*4*micro coulomb/((12+x)^2) =>12+x =x* sqrt(2) =>12 =0.414*x =>x =28.99 cm Point X0 = (-28.99 cm,00) Electric field is 0 at a distance of 28.99 cm to the left of -ve charge at origin
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