/2018 11:59 PM 37.1/100 3/29/2018 05:41 PM Gradeb Print Calculator Periodic Tabl
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/2018 11:59 PM 37.1/100 3/29/2018 05:41 PM Gradeb Print Calculator Periodic Table n 8 eral Chemistry 4th Edition University Science Books presented by Sapling Leaming Mapo Calculate the pH for each of the following cases in the titration of 50.0 mL of 0.170 M HCIO(aq) with 0.170 M KOH(aq), The ionization constant for HClO can be found here. Number (a) before addition of any KOH 4.11 Number 7.50 equal concentrations of monoprotic titrant and the equivalence point would occur when the added volumes are equal (50.0 mL of KOH added) so at point (c), we are 300/50.0 60.0% of the way to (c) after addition of 30.0 mL of KOH | the equivalence point. If 60.0% of the acid has reacted. then 40 % remains, and 60.0% of the conjugate base 8.10 has beekt formed so [CIO THCIOj 60.040.0 equation. (d) after addition of 50.0 mL of KOH CIO HCIO Number (e) after addition of 60.0 mL of KOH O Previous ?Give Up & View Soludn #Try Again eNext Exit- about us careers privacy policy terms of use 4Explanation / Answer
c)
millimoles of HClO = 50 x 0.170 = 8.5
millimoles of KOH = 30 x 0.170 = 5.1
HClO + KOH ---------------------> KClO + H2O
8.5 5.1 0 0
3.4 0 .0 5.1 5.1
pH = pKa + log (KClO / HClO)
pH = 7.40 + log (5.1 / 3.4)
pH = 7.58
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