Two equal positive point charges Q are on the x axis at x = 1/2 a and x = - 1/2

Question

Two equal positive point charges Q are on the x axis at x = 1/2 a and x = - 1/2 a. Obtain an expression for the electric field on the y axis as a function of y. (b) A bead of mass m, which has charge q, moves along the y axis on a thin frictionless taut thread. Find the electric force that acts on the bead as function of y and determine the sign of q such that this force always points away from, the origin. The bead is initially at rest at the origin If it is given a slight midge in the +y direction, how fast will the bead be traveling the instant the net force on it is a maximum? (Assume any effects due to gravity are negligible.)

Explanation / Answer

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net acceleration=(g+(qE/m))
speed after height h=sqrt(2*acceleration*height)=sqrt(2*(g+(qE/m))*h)

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