On her way in to work on morning, an evil chemistry professor notices an 80 kg b

Question

On her way in to work on morning, an evil chemistry professor notices an 80 kg bag of cats dangling next to the science building, hanging by a (massless) thread, The chemistry professor cries, but through her tears she sees the thread is running over a massless, frictionless pulley mounted to the edge of the horizontal roof. She pulls a periscope out of her back pocket and uses it to determine that the massless rope is attached to a concrete block sitting on the roof. If the mass of the concrete block is 250 kg and the coefficent of static friction between the roof and the conrete block is 0.58, what is the minimum force the evil professor must apply to the bag in order to overcome static friction and lower the cats to safety?

Looking for a detailed answer, Please include any formulas used.

Explanation / Answer

F(N)block = F(N)cats mue*m(block)*g = m(bag)*g + F So the force the professor would need to exert is: F = mue*m(block)*g - (m(bag)*g) F = 0.58*250*9.8 - (80*9.8) F = 637 N

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