A billiard ball moving at 5.60 m/s strikes a stationary ball of the same mass. A

Question

A billiard ball moving at 5.60 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.75 m/s at an angle of 32.0 degree with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision. magnitude m/s direction degree (with respect to the original line of motion)

Explanation / Answer

from momentum conservation, initial momentum = final momentum x-direction, m x 5.60 = m x 4.75 x cos(32) + m x v_x ==> v_x = 1.571772 m/s y-direction, 0 = m x 4.75 x sin(32) + m x v_y ==> v_y = - 0.529919 m/s magnitude of velocity = 1.658699 m/s direction (from the original dir.) = - 18.63 degrees

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