A billiard ball moving at 5.70 m/s strikes a stationary ball of thesame mass. Af

Question

A billiard ball moving at 5.70 m/s strikes a stationary ball of thesame mass. After the collision, the first ball movesat 4.78 m/s, at an angleof 33.0° with respect to the original line ofmotion. (a) Find the velocity (magnitude and direction) of the second ballafter collision.
m/s
°(with respect to the original line of motion, include the sign ofyour answer; consider the sign of the first ball's angle)
(a) Find the velocity (magnitude and direction) of the second ballafter collision.
m/s
°(with respect to the original line of motion, include the sign ofyour answer; consider the sign of the first ball's angle)

Explanation / Answer

m*5.7=m*4.78cos33+mvcos................(1) 0       =m*4.78sin33-mvsin   ..................(2) these two equations are obtained by resolving momentum into Xand Y components. solving these two we will get v=10.04m/sec =15.02degree.      

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