A monatomic ideal gas is compressed adiabatically from a pressure of 1.47 x 10^5

Question

A monatomic ideal gas is compressed adiabatically from a pressure of 1.47 x 10^5 Pa and volume of 270 L to a volume of 44.0 L. (a) What is the new pressure of the gas? (b) How much work is done on the gas? For part (a) I got the correct answer 3.04 x 10^6, simply from P1V1^y=P2V2^y, y(constant for monatomics) = 1.67. Plug and chug, very simple. I'm having trouble with part (b). My book says that work done "BY" gas is this equation, W = (P1V1 - P2V2)/y - 1 which gives me a very large negative number which is incorrect. My homework online spits out a calculation of an unknown five digit number (negative) that is the correct answer. I guess my question is...how much work is done "ON" the gas, not "BY" the gas. I only need part (b) answered! Thank you!

Explanation / Answer

According to the formula
W = (1/(1-y))(p2v2-p1v1)

     y = 1.67, p1= 1.47 x 105 Pa, V1 = 270L, P2 = 3.04x106pa(from part-a you got it),V2 = 44L

    w = -140.40 X 106J

A negative number in the workdone indicates workdone on the Gas.

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