A car of mass = 1500 traveling at 45.0enters a banked turn covered with ice. The

Question

A car of mass = 1500 traveling at 45.0enters a banked turn covered with ice. The road is banked at an angle , and there is no friction between the road and the car's tires. (Figure 1) . Use = 9.80 throughout this problem.Now, suppose that the curve is level () and that the ice has melted, so that there is a coefficient of static friction between the road and the car's tires.(Figure 2) What is , the minimum value of the coefficient of static friction between the tires and the road required to prevent the car from slipping? Assume that the car's speed is still 45.0 and that the radius of the curve is given by the value you found for in Part A.

Explanation / Answer

for the first case tan(theta)=v^2/r*g...................1 value of theta should be given here from equation1 calculate value of r then for the second part mu=v^2/r*g put value of r and solve to get mu

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