The equation of a transverse wave traveling along a very long string is y=(7.0)s

Question

The equation of a transverse wave traveling along a very long string is y=(7.0)sin(0.060?*x +12.0? * t), where x and y are expressed in centimeters and t in seconds. a. Determine the amplitude of propagation of the wave. (7 cm) b. Determine the wavelength of the wave. (cm) c. Determine the frequency of the wave. (Hz) d.Determine the speed of the wave. (cm/s) e. Determine the maximum transverse speed of a particle in the string.(cm/s) f,What is the transverse displacement at x = 4.50 cm when t = 0.24 s?

Explanation / Answer

y=(7.0)sin(0.060?*x +12.0? * t),.............k = 0.06.........w = 12......k = 2pi/lambda....and w = 2pif...........so.......b) lambda = 6.28/0.06 = 104.7...answer....and ...c) "f" = 12/6.28 = 1.91 Hz....answer....... d) speed = lambda*f = 200.06 m/s....answer...

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