The equation below describes a physical situation: (1.70kg)|3. 30 + (1.70kg)| 98

Question

The equation below describes a physical situation: (1.70kg)|3. 30 + (1.70kg)| 98|(2.35m)sin30° = (1.70kg)| 4 60s +0.320(1.70kg)|9.80s!(2.35m)cos30° Which description best fits the equation? A 1.70 kg block slows down while sliding down a frictionless plane inclined at a 30° angle. A 1.70 kg block slows down while sliding down a plane with .-0.320, with the plane inclined at a 30° angle. A 1.70 kg block speeds up while sliding up a frictionless plane inclined at a 30° angle. A 1.70 kg block speeds up while sliding down a plane with .-0.320, with the plane inclined at a 30° angle. A 1.70 kg block slides over the top of an inclined plane and then descends on the other side. Both planes, inclined at a 30° angle, have .-0.320. a. b, c. d, c.

Explanation / Answer

The answer is (d).

Because at the left hand side of the equation, the block has initial speed of 3.3 m/s with height 2.35 m. Then it starts sliding and its speed rise up to 4.60 m/s and here is a frictional force 0.320. Thus the two side of the equation balance.

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