A transverse periodic wave is represented by the equation y(x, t) = 1.50 cm sin(

Question

A transverse periodic wave is represented by the equation y(x, t) = 1.50 cm sin(1,500 rad/s t - 10.0 m-1 x). Another transverse wave is represented by the equation y(x, t) = 1.50 cm sin(1,500 rad/s t - 10.0 m-1 x). What is the equation that represents the superposition of the two waves Possible Answers: y(x, t) = 3.0 cm sin(1,500 rad/s t - 10.0 m-1 x) y(x, t) = 3.0 cm sin(1,500 rad/s t) cos(10.0 m-1 x) y(x, t) = +3.0 cm cos(1,500 rad/s t) sin(10.0 m-1 x) y(x, t) = 3.0 cm sin(1,500 rad/s t + 10.0 m-1 x)

Explanation / Answer

since both the waves are equal in frequency,wavelength,amplitude,if they superpose resulting wave will be double the amplitude. so,resulting wave is y(x, t) = 3.0 cm sin(1,500 rad/s t - 10.0 m-1 x)

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