The figure shows a lower leg being exercised. It has a 49-N weight attached to t

Question

The figure shows a lower leg being exercised. It has a 49-N weight attached to the foot and is extended at an angle (theta) with respect to the vertical. Consider a rotational axis at the knee, as indicated. (a) When (theta) = 82?, find the magnitude of the torque that the weight creates. (b) At what angle (theta) does the magnitude of the torque have a value of 11 N?m?

The figure shows a lower leg being exercised. It has a 49-N weight attached to the foot and is extended at an angle (theta) with respect to the vertical. Consider a rotational axis at the knee, as indicated. (a) When (theta) = 82?, find the magnitude of the torque that the weight creates. (b) At what angle (theta) does the magnitude of the torque have a value of 11 N?m?

Explanation / Answer

torque = r×F=rFsin=0.55*49sin82 =26.6Nm

now torque = 11Nm find =?

same formula

t=rFsin ----->11/(0.55*49)=sin----=24 degree

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