A beam of unpolarized light of intensity Io passes through a series of ideal pol
ID: 2207881 • Letter: A
Question
A beam of unpolarized light of intensity Io passes through a series of ideal polarizing filters with their polarizing directions turned to various angels as shown in the figure. A. what is the light intensity in terms of Io at points A, B ,C? B. if we remove the middle filter, what will be the light intensity at point C?
A beam of unpolarized light of intensity Io passes through a series of ideal polarizing filters with their polarizing directions turned to various angels as shown in the figure. A. what is the light intensity in terms of Io at points A, B ,C? B. if we remove the middle filter, what will be the light intensity at point C?Explanation / Answer
At point A I = 1/2*Io Use Malus Law to find I at B and C IB = IA*cos^2(?) = 1/2*Io*cos^2(60) = 0.125*Io IC = IB*cos^2(?) = 0.125*Io*cos^2(30) = 0.09375*Io
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