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Three long, parallel conductors each carry a current of I = 2.28 A. The figure b

ID: 2207670 • Letter: T

Question

Three long, parallel conductors each carry a current of I = 2.28 A. The figure below is an end view of the conductors, with each current coming out of the page. Taking a = 1.25 cm, determine the magnitude and direction of the magnetic field at the following points.

A) Point A Magnitude direction

Three long, parallel conductors each carry a current of I = 2.28 A. The figure below is an end view of the conductors, with each current coming out of the page. Taking a = 1.25 cm, determine the magnitude and direction of the magnetic field at the following points. A) Point A Magnitude direction

Explanation / Answer

B = I/2r

B magnetic field due to a wire

I current in th wire

r distance from the wire

= 410-7 Tm/A

fields due to I1 (r = 2 a) I2 (r = 2 a) I3 ( r= 3a) at point A

B1 = B2 = 2.579 * 10-5

B3 = 2.432 *10-5

Total magnitude is 2(B1) + B3 =  6.079*10-5 T Direction is found using right hand rule i.e downwards

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