Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc
ID: 2202346 • Letter: J
Question
Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 18.0 m/s at an angle 42.0 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground. --After catching the ball, Sarah throws it back to Julie. The ball leaves Sarah's hand a distance 1.5 meters above the ground, and is moving with a speed of 14.0 m/s when it reaches a maximum height of 10.0 m above the ground. What is the speed of the ball when it leaves Sarah's hand? -----> I got 19.05m/s 1)6) How high above the ground will the ball be when it gets to Julie? (note, the ball may go over Julie's head.)Explanation / Answer
T=2vsin/g=2.422s
distance d= vcos*T=17.975 m
ucos=d/1.796 = 10s
11=usin*1.796^2/2g=> usin=66.83
dividing we get tan=6.68 , =81.49
velocity =67.57 m/s
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