Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 14.0 m/s at an angle 61.0 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.

After catching the ball, Sarah throws it back to Julie. The ball leaves Sarah's hand a distance 1.5 meters above the ground, and is moving with a speed of 8.0 m/s when it reaches a maximum height of 11.0 m above the ground.
What is the speed of the ball when it leaves Sarah's hand?

Explanation / Answer

Horizontal component of velocity, vcos = 8 m/s
max height, v^2 sin^2 /2g = (11-1.5) = 9.5

v^2 sin^2 = 186.2

v^2 sin^2 + (vcos)^2 = v^2

v = 15.81 m/s

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