A diverging lens has a focal length of magnitude 17.2 cm. (a) Locate the images

Question

A diverging lens has a focal length of magnitude 17.2 cm. (a) Locate the images for each of the following object distances. 34.4 cm distance cm location 17.2 cm distance cm location 8.6 cm distance cm location (b) Is the image for the object at distance 34.4 real or virtual? Is the image for the object at distance 17.2 real or virtual? Is the image for the object at distance 8.6 real or virtual? (c) Is the image for the object at distance 34.4 upright or inverted? Is the image for the object at distance 17.2 upright or inverted? Is the image for the object at distance 8.6 upright or inverted? (d) Find the magnification for the object at distance 34.4 cm. Find the magnification for the object at distance 17.2 cm. Find the magnification for the object at distance 8.6 cm.

Explanation / Answer

f =17.2 p =34.4 1/f =1/p+1/q 1/17.2 = 1/34.4 + 1/q q = 34.4 same size , virtual p= 17.2 putting in formula q = 0 image is virtual and at infinity

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