A diver makes a series of summersaults during a diving competition. Stretched ou

Question

A diver makes a series of summersaults during a diving competition. Stretched out he rotates about an axis which is horizontal and perpendicular to his body. He then goes into a tuck reducing his moment of inertia by a factor of 3.896 making now 0.928 revolutions per second. What was his initial angular velocity in revolutions per second (see sheet 27). Indicate with a negative (positive) sign whether inclusion of air resistance and thus inclusion of an external torque would (not) modify your answer.

Explanation / Answer

law of conservation of angular momentum states

initial momentum = final momentum

I11 = I22

given I2 = I1 / 3.896

2 = 0.928 rev /s

1 = I22 / I1 = 0.928 / 3.896 = 0.238 rev/s

initial angular velocity =  0.238 rev/s

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