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A 12-N force is applied at the point x=3m, y=1m. Find the torque about the origi

ID: 2200089 • Letter: A

Question

A 12-N force is applied at the point x=3m, y=1m. Find the torque about the origin if the force points in (a) the x direction, (b) the y direction, and (c) the z direction. torque=____Nm

Explanation / Answer

Torque is a measure of how much a force acting on an object causes that object to rotate. The object rotates about an axis, which we will call the pivot point, and will label 'O'. .....................F-----> (11 N) ....................... y =1 m. O----------------- The magnitude of torque depends on three quantities: First, the force applied; second, the perpendicular length of the lever arm connecting the axis to the point of force application; and third, the angle between the two. In symbols: tau (t) = r x F or r F sin(theta) if force is applied at an angle. in our case force is applied parallel to x axix and axis of ration is y axis, (theta = 90) so torque (tau) = r x F ; as (sin 90 = 1, F = 12 N, r = y = 1 meter) torque (tau) = 1 x 12 = 12 N-m Remember "perpendicular distance" to the force from the axis which is 1 not 3 meter
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