1-Calculate the tension Ft in the wire that supports the 46kg beam shown in the

Question

1-Calculate the tension Ft in the wire that supports the 46kg beam shown in the figure(Figure 1) . 2-Calculate the magnitude of the force Fw exerted by the wall on the beam. 3-Calculate the direction of the force Fw exerted by the wall on the beam. http://im16.gulfup.com/kkeb1.jpg

Explanation / Answer

Ft occurs along the string........ its vertical component is Ftsin40................................... equating vertical components we get Ftsin40=mg.....=>Ft=mg/sin40.....=>Ft=46*9.8/0.6428......=>Ft=701.3 newton................... 1)Tension Ft in wire=701.3 newton............................................................................................. 2)Equating horizontal forces Fw=Ftcos40=701.3*0.766=537.23 newton........................... 3)the force exerted by the wall acts towards the beam..

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