A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At

Question

A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. Att = 0the puck is moving to the right at 3.0 m/s.

a)Calculate the magnitude of the velocity of the puck after a force of 25.2N directed to the right has been applied for 5.60 x 10^-2 s.
b)What is the direction of the velocity of the puck after a force of 25.2N directed to the right has been applied for 5.60 x 10^-2 s.

+x direction
-x direction

c)If instead, a force of 12.1N directed to the left is applied from t = 0to t=5.60 x 10^-2 s, what is the magnitude of the final velocity of the puck?

d)What is the direction of the final velocity of the puck in this case?

+x direction
-x direction

Explanation / Answer

a) Impulse(1) = 25.2 * .056 = 1.41 Ns Dv(1) = I(1)/m = 8.82 m/s v(1) = 3 + 8.82 = 11.82 m/s b) +x direction c) I(2) = -12.1*.056 = -.6776 Ns Dv(2) = -.6776/.167 = -4.057 m/s v(2) = 3. - 4.057 = -1.057 m/s d) -x direction

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