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A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At

ID: 1520059 • Letter: A

Question

A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t=0 the puck is moving to the right at 3.02 m/s .

Part A

Calculate the magnitude of the velocity of the puck after a force of 25.3 N directed to the right has been applied for 4.5×102 s .

Express your answer using two significant figures.

Part B

What is the direction of the velocity of the puck after a force of 25.3 N directed to the right has been applied for 4.5×102 s .(right or left?)


Part C

If instead, a force of 12.4 N directed to the left is applied from t=0 to t= 4.5×102 s , what is the magnitude of the final velocity of the puck?

Express your answer using two significant figures.

Part D

What is the direction of the final velocity of the puck in this case?(right/left?)

"correvt answers please"

Part B

What is the direction of the velocity of the puck after a force of 25.3 N directed to the right has been applied for 4.5×102 s .(right or left?)


Explanation / Answer

Part A)   Here, applied force = Rate of change in momentum

=>   25.3 * 4.5×102    =   0.160 * ( v - 3.02)

=>   v = 10.135 m/sec             -----------------> magnitude of the velocity of the puck after

Part B)     direction of the velocity of the puck = right

Part C)     Here,    - 12.4 * 4.5×102   =   0.160 * ( v - 3.02)

=>   v =    0.4675 m/sec             -------------------->   magnitude of the final velocity of the puck

Part D)     direction of the final velocity of the puck in this case   =   towards left