A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At
ID: 1520059 • Letter: A
Question
A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t=0 the puck is moving to the right at 3.02 m/s .
Part A
Calculate the magnitude of the velocity of the puck after a force of 25.3 N directed to the right has been applied for 4.5×102 s .
Express your answer using two significant figures.
Part B
What is the direction of the velocity of the puck after a force of 25.3 N directed to the right has been applied for 4.5×102 s .(right or left?)
Part C
If instead, a force of 12.4 N directed to the left is applied from t=0 to t= 4.5×102 s , what is the magnitude of the final velocity of the puck?
Express your answer using two significant figures.
Part D
What is the direction of the final velocity of the puck in this case?(right/left?)
"correvt answers please"
Part B
What is the direction of the velocity of the puck after a force of 25.3 N directed to the right has been applied for 4.5×102 s .(right or left?)
Explanation / Answer
Part A) Here, applied force = Rate of change in momentum
=> 25.3 * 4.5×102 = 0.160 * ( v - 3.02)
=> v = 10.135 m/sec -----------------> magnitude of the velocity of the puck after
Part B) direction of the velocity of the puck = right
Part C) Here, - 12.4 * 4.5×102 = 0.160 * ( v - 3.02)
=> v = 0.4675 m/sec --------------------> magnitude of the final velocity of the puck
Part D) direction of the final velocity of the puck in this case = towards left
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