A block of mass M is attached to a spring with a spring constant 2k, pulled back

Question

A block of mass M is attached to a spring with a spring constant 2k, pulled back a distance 2d, and released. A block of mass M is attached to a spring with a spring constant 2k, pulled back a distance d, and released. A block of mass M is attached to a spring with a spring constant k, pulled back a distance d, and released. A block of mass (1/2)M is attached to a spring with a spring constant k, pulled back a distance d, and released. A block of mass M is attached to a spring with a spring constant k, pulled back a distance 2d, and released.

Explanation / Answer

The maximum force on the block can be calculated using the Hooke's law F = kx Here, k is the spring constant and x is the compression or stretched distance i) Spring constant is k , stretched distance is d/2 F1 = k (d/2) =1/2 (kd) Rank - (1) ii) Spring constant is 2k , stretched distance is 2d F2 = 2k (2d) = 4 (kd) Rank - (3) iii) Spring constant is 1/2k , stretched distance is d F3 = 1/2k (d) = 1/2 (kd) Rank - (1) iv)Spring constant is k , stretched distance is d F4 = k (d) = kd Rank - (2) v)Spring constant is k , stretched distance is d F5 = k (d) = kd Rank - (2) F2 > (F4 = F5) > ( F1 = F3 )

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