A linearly polarized beam of light of intensity I 0 is propagating in the + z di
ID: 2193681 • Letter: A
Question
A linearly polarized beam of light of intensityI0is propagating in the +zdirection and its direction of polarization makes an angle of 64.0 with the x-axis (the angle between the initial direction of polarization and the transmission axis of the first polarizer is 26.0 as described below). Two linear polarizing sheets are lined up perpendicular to the beam. The first sheet has its transmission axis at an angle?1= 90 with respect to thex-axis. The transmission axis of the second is variable.
1.The second polarizer is set at various angles within the range?2= 0 to 90 Calculate the intensity of the light after it has passed through the second polarizer for the following values of?2. Express each answer as a fraction ofI1.
At?2= 0I2/I1=
A linearly polarized beam of light of intensityI0is propagating in the +zdirection and its direction of polarization makes an angle of 64.0½ with the x-axis (the angle between the initial direction of polarization and the transmission axis of the first polarizer is 26.0½ as described below). Two linear polarizing sheets are lined up perpendicular to the beam. The first sheet has its transmission axis at an angle?1= 90½ with respect to thex-axis. The transmission axis of the second is variable. 1.The second polarizer is set at various angles within the range?2= 0 to 90½ Calculate the intensity of the light after it has passed through the second polarizer for the following values of?2. Express each answer as a fraction ofI1. At?2= 0½I2/I1= 2. At?2= 25.0½I2/I1= 3.At?2= 90½I2/I1=
Explanation / Answer
the polarizer decreases by ratio of cos() so if Io falls on first the angle between them is 26 so fallss by Iocos(26.) and comes out at 90 degrees. similarly the second polarizer also decreases the intensity by Iocos(26)cos(90-theta). put value of theta and get all your answers
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