A linearly polarized beam of light of intensity I 0 is propagating in the + z di

Question

A linearly polarized beam of light of intensity I0 is propagating in the +z direction and its direction of polarization makes an angle of 66ݰ with the x-axis (the angle between the initial direction of polarization and the transmission axis of the first polarizer is 24ݰ as described below). Two linear polarizing sheets are lined up perpendicular to the beam. The first sheet has its transmission axis at an angle ݸ1 = 90ݰ with respect to the x-axis. The transmission axis of the second is variable. (See lower panels of the figure.)

1)

I 1 / I0 = Correct

2)Calculate the electric field amplitude E1 of the light after it has passed through the first polarizer. Express your answer as a fraction of the electric field amplitude E0 of the initial beam.

E 1 / E0 = Correct

3)The second polarizer is set at various angles within the range ? 2 = 0 to 90

A linearly polarized beam of light of intensity I0 is propagating in the +z direction and its direction of polarization makes an angle of 66à  degree with the x-axis (the angle between the initial direction of polarization and the transmission axis of the first polarizer is 24à  degree as described below). Two linear polarizing sheets are lined up perpendicular to the beam. The first sheet has its transmission axis at an angle à ¸1 = 90à  degree with respect to the x-axis. The transmission axis of the second is variable. (See lower panels of the figure.)

Explanation / Answer

you got first 2 parts right so here is answers for third pard

I2 = I1 cos(theta2 -theta1)^2

so I2/I1 = cos(theta2-theta1)^2

cos( 0 - 90)^2 = 0

b) cos( 51)^2=0.396

c) cos(90-90)^2 = 1

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