The stainless steel annular disk is allowed to rotate on a frictionless table wi

Question

The stainless steel annular disk is allowed to rotate on a frictionless table with the rotation axis at its center. The disk has a small cylinder rigidly mounted at the top concentrically. The cylinder's radius is 13.2 mm, and the mass of the cylinder is negligible. A string is wrapped around the cylinder, and a hanging mass of 21.1 g is tied at the other end of the string. When the mass falls under gravity, it causes the stainless steel annular disk to rotate. Ignoring the string's mass, and assuming that the string's motion is frictionless, what is the angular acceleration of the stainless steel annular disk

Explanation / Answer

You need to calculate the torque. T = force*radius of the cylinder Then the angular analogy to Newton's 2nd (F=ma) is T = I*alpha where I is the moment of inertia and alpha is the angular acceleration.

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