4-19 A parachutist of mass m falls, with upward drag force on parachute of R. a)

Question

4-19 A parachutist of mass m falls, with upward drag force on parachute of R. a) What is acceleration of parachutist? b) R is greater than mg when parachute first opens. What then is the direction of the acceleration? What is the direction of the velocity? c) Calculate the acceleration of the falling parachutist when the drag force is 1000N and the mass of the parachutist is 80kg. NEglect mass of parachute. d) How large a drag force will produce terminal velocity?

Explanation / Answer

a)mg-R=ma =>a=g-(R/m) b)a=R/m -g upwards a v is upwards c)1000-80*9.8=80*a =>a=2.7m/s^2 upwards d)F drag=mg=80*9.8=784N

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