A flat coil enclosing an area of 0.12 m2 is rotating at 61 rev/s, with its axis

Question

A flat coil enclosing an area of 0.12 m2 is rotating at 61 rev/s, with its axis of rotation perpendicular to a 0.20 T magnetic field. (a) If there are 1000 turns on the coil, what is the maximum voltage induced in the coil? V (b) When the maximum induced voltage occurs, what is the orientation of the coil with respect to the magnetic field? The plane of the coil is parallel to the magnetic field. The plane of the coil is at a 61° angle to the magnetic field. The plane of the coil is perpendicular to the magnetic field. The plane of the coil is at a 41° angle to the magnetic field.

Explanation / Answer

A flat coil enclosing an area of 0.07 m2 is rotating at 61 rev/s, with its axis of rotation perpendicular to a 0.18 T magnetic field. If there are 995 turns on the coil....
___________V

answer(you put values according to you okay)

E = N (d/dt)

= BAcos(wt)

take derivative of with respect to t
you get d = BAwsin(wt)
E = NBAwsin(wt)
sin max when wt = 90° or /2 ...sin(90) = 1 = sin(/2)
convert rev/s to rad/sec ........... 61rev/sec = 122 rad/s = w
E = (995)(0.07m^2)(.18T)(122)(1)
E = 4.8KV = voltage

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