d) NOTE : The data for this problem is written in exponential form. For example:
ID: 2186877 • Letter: D
Question
d) NOTE: The data for this problem is written in exponential form. For example: 2.1e-15 means 2.1x10-15.
A certain nucleus at rest suddenly decays into three particles, two of which are charged and can be easily detected. The data gathered for these two particles is:
- Particle 1 has mass m1 = 2.69e-25 kg moving at speed v1 = 5.03e+06 m/s at ?1 = 58.2o.
- Particle 2 has mass m2 = 1.47e-25 kg moving at speed v2 = 8.23e+06 m/s at ?2 = 235o.
Find p3, the momentum of the third piece.
4i kg-m/s + 5j kg-m/s
e) A symmetrical rowboat, mass M = 124 kg, length L = 6.15 m, points toward the shore. Harry, mass m = 95.2 kg, stands in the back of the boat, distance d = 38.9 m from the shore. If Harry now walks to the front of the boat, how far will he be from the shore?
6 m
f) Mass m1 = 5.1 kg, moving at initial velcity v10 = 7.47i m/s, collides head-on with mass m2 = 3.44 kg moving at initial velocity v20 = -7.01i m/s. After the collision both particles bounce backward: m1 at velcity v1 = -7.31i m/s, and m2 at velocity v2 = 6.05i m/s. Find e, the coefficient of restitution for this collision.
7
Explanation / Answer
for d, momentum is conserved in all directions, so... Break things down into the x (i) and y (j) components X (i): 2.69e-25*5.03e6*cos(58.2)+1.47e-25*8.23e^6*cos(235)= negative momentum in i direction do the same for the Y (j) direction ---------- e) use conservation of momentum (but use speeds relative to the point in the water (if he's walking at 1 m/s relative to the boat, he may only be traveling 0.7 m/s relative to the water, so his momentum would be 0.7*mass. (I just made these numbers up, but you get the point) ------ coefficient of restitution = (final velocity of object 2 - final velocity of object 1)/(initial velocity of a - initial velocity of b)
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