The figure shows an arrangement of 15 identical disks that have been glued toget
ID: 2186453 • Letter: T
Question
The figure shows an arrangement of 15 identical disks that have been glued together in a rod-like shape of lengthL= 1.8500 m and (total) massM= 179.0 mg. The arrangement can rotate about a perpendicular axis through its central disk at pointO.(a)What is the rotational inertia of the arrangement about that axis? Give your answer to four significant figures.(b)If we approximated the arrangement as being a uniform rod of massMand lengthL, what percentage error would we make in using the formula in Table 10-2eto calculate the rotational inertia?
(a) Number Units radrad/srad/s^2kg?m^2N?mkg?m^2/srad^2/s^2Explanation / Answer
I1 = mR^2/2 + 14 X MR^2/2 + 2 MR^2( (2r)^2 + (4r)^2 + (6r)^2 + (8r)^2 + (10r)^2 + (12r)^2 + (14r)^2) b. I2= 1/12[ML^2 ] l= 15R percent error = I1- I2 / I1
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