A grinding wheel is in the form of a uniform solid disk of radius 7.04 cm and ma

Question

A grinding wheel is in the form of a uniform solid disk of radius 7.04 cm and mass 2.10 kg. It starts from rest and accelerates uniformly under the action of the constant torque of 0.596 N middot m that the motor exerts on the wheel. How long does the wheel take to reach its final operating speed of 1 160 rev/min? s Through how many revolutions does it turn while accelerating? You appear to have calculated the number of revolutions correctly using your incorrect result for the time from part (a). rev

Explanation / Answer

moment of inertia of solid disk = mr^2/2

= 5.2039*10^-3

= I*

0.596 = 5.2039*10^-3*

= 114.52 rad/s2

= t

t = 1.06 sec

(1160*2/60)^2 = 2

= 64.42 rad

= 10.25 rev

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