A block weight w=40.0 N sits on a frictionless inclined plane, which makes an an

Question

A block weight w=40.0 N sits on a frictionless inclined plane, which makes an angle theta=35 degrees, with respect to the horizontal, as shown in the figure. A force of magnitude F=22.9 N, applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed.

1. What is the W_F, the work done on the block by the force (F) as the block moves a distance L= 2.50m up the incline?

2. What is the W_N, the work done on the block by the normal force as the block moves a distance L= 2.5m up the inclined plane?

Explanation / Answer

F = mgsin25

work = F*L

= Wsin35*2.50

= 57.36 J

by normal force = 0

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