The pictures below depict cannonballs of two different masses projected upward a

Question

The pictures below depict cannonballs of two different masses projected upward and forward. The cannonballs are projected at various angles above the horizontal, but all are projected with the same horizontal component of velocity. Consider the starting height differences to be NEGLIGIBLE (e.g. they all pretty much start from the same height). The only difference between each is the mass of the cannonball, the angle of projection and the initial velocity (shown as v on the diagram). Ignore air resistance. Rank according to the horizontal distance traveled by the balls. Largest Smallest All distances traveled are the same. Carefully explain your reasoning for your selection(s). You may show calculations &/or equations as part of your explanation.

Explanation / Answer

as all have same horizontal speed ,so horizontal distance will depend upon the time taken to come to ground. the larger the time it takes to come back to ground,the larger will be the horizontal distance(as distance=velocity*time,horizontal velocity of all 3 are same,20 m/s) now,time taken to reach ground is given by 2*v*sin(theta)/g where v=initial launch speed theta=angle with horizontal of the launch velocity so here in first case,time=2.357 sec for second case time=2.357 sec for 3rd case, time=4.083 sec so horizontal distance travelled by case 1 and case 2 will be equal and case 3 will be higher than case 1 and case 2. so case 3>case1=case2

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