The picture below shows water forced out of a fire extinguisher by compressed ai

Question

The picture below shows water forced out of a fire extinguisher by compressed air. The acceleration of gravity is 9.8 m/s 2 .The water jets out at speed vjet = 5.49 m/s from a nozzle located at height h = 1.43 m above the water level inside the extinguisher. Calculate the gauge pressure of the compressed air inside the extinguisher, that is, the pressure difference P gauge air = P inside air P outside air . Note: Water density is 1000 kg/m3 and the extinguisher’s body is much wider than the water jet. Answer in units of kPa.

Explanation / Answer

using bernouli'sequation,

P + row*g*h + row*v^2 /2 = constant

Pin + 0 + 0 =   Pot + (1000 x 9.8 x 1.43) + (1000 x 5.49^2 /2 )

Pin - Pout = 29084.04 Pa = 29.1 kPa

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