(a) What is the tangential acceleration of a bug on the rim of a 11.0-in.-diamet

Question

(a) What is the tangential acceleration of a bug on the rim of a 11.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 76.0 rev/min in 3.30 s?
___ m/s2

(b) When the disk is at its final speed, what is the tangential velocity of the bug?
___m/s

(c) One second after the bug starts from rest, what is its tangential acceleration?
___ m/s2

(d) One second after the bug starts from rest, what is its centripetal acceleration?
___ m/s2

(e) One second after the bug starts from rest, what is its total acceleration?
___m/s2
___

Explanation / Answer

a) w= at,,,,,,,,,,,,, 76 rpm=7.9 rad/s =a*3.3,,,,,,,,a=2.4 rad/s^2,,,,,,,,,,,,,,,,,, b) tangential velocity of the bug = wr=7.9*0.0254*11=2.2 m/s,,,,,,,,,,, c) tangential acceleration=r*angular accealration=0.92 m/s^2,,,,,,,, d)a=2.4 rad/s^2 e)0.92 m/s^2,,,,,,,,2.4 rad/s^2

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.