(a) What is the tangential acceleration of a bug on the rim of a 11.0-in.-diamet

Question

(a) What is the tangential acceleration of a bug on the rim of a 11.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 77.0 rev/min in 4.80 s? .256 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m/s2 (b) When the disk is at its final speed, what is the tangential velocity of the bug? m/s (c) One second after the bug starts from rest, what is its tangential acceleration? Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m/s2 (d) One second after the bug starts from rest, what is its centripetal acceleration? m/s2 (e) One second after the bug starts from rest, what is its total acceleration? m/s2

Explanation / Answer

the centripetal acceleration (or radial accel) is v^2/r = (1.13m/s)^2/0.14m = 9.12m/s/s (make sure you convert 5.5 inches to meters) the total accel is then sqrt[a tangential^2 + a radial^2] to find the direction, draw a triangle with the radial accel as one leg, the tangential accel as the shorter leg, and the hypotenuse representing the resultant acceleration then show that if theta is the angle with respect to the radius line, tan(theta) = a tangential/a radial => theta = ArcTan(a tangential/a radial)

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.